Не происходит вставка в базу данных, помогите найти ошибку в синтаксисе?
Сергей Субботин3 ответов
<?php
function insert($name, $desc, $year, $rating, $poster, $category_id) {
$mysqli = new mysqli("localhost", "root", "", "kinomonster");
if(mysqli_connect_errno()) {
print_f("соедтнение не установлено");
exit();
}
$mysqli->set_charset("utf8");
$query = "INSERT INTO movie VALUE(null, $name, $desc, $year, $poster, now(), $category_id)";
$result = false;
/* if($mysqli->query($query)) {
$result = true;
}*/
if( $mysqli->query($query) or die( $mysqli->error ) ) {
$result = true;
}
return $result;
}
$xml = simplexml_load_file("xml/movies.xml") or die("Error: Cannot great object");
$title = null;
$title_orign = null;
$post = null;
$rating = null;
$year = null;
foreach ($xml as $movie_key => $movie) {
$title = $movie->title_russian;
$title_orign = $movie->title_original;
$year = $movie->year;
$post = $movie->title_russian;
foreach ($movie->poster->big->attributes() as $poster_key => $poster) {
$post = $poster;
}
if($movie->imdb) {
$rating = $movie->imdb->attributes()["rating"];
} else {
$rating = null;
}
insert($title, $title_orign, $year, $rating, $post, 1);
}
echo "<pre>";
print_r($xml);
echo "</pre>";
?>